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DataStructure/Array

Two Sum

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].


My solution:


class Solution:
def twoSum(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: List[int]
"""
for i in range(len(nums)):
if target - nums[i] in nums:
if i != nums.index(target - nums[i]):
return [i, nums.index(target - nums[i])]

return None


Good solution:

class Solution:
def twoSum(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: List[int]
"""
dist = {}

for i in range(len(nums)):
if target - nums[i] in dist:
return [dist[target - nums[i]], i]
dist[nums[i]] = i

return None

Instead of using dict(), use {}.

It's good for runtime.

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