Given an array containing n distinct numbers taken from 0, 1, 2, ..., n
, find the one that is missing from the array.
Example 1:
Input: [3,0,1] Output: 2
Example 2:
Input: [9,6,4,2,3,5,7,0,1] Output: 8
Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?
My soultion:
class Solution:
def missingNumber(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
n = len(nums)
return n*(n+1)//2 - sum(nums)
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