Implement strStr().
Return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
Example 1:
Input: haystack = "hello", needle = "ll" Output: 2
Example 2:
Input: haystack = "aaaaa", needle = "bba" Output: -1
Clarification:
What should we return when needle
is an empty string? This is a great question to ask during an interview.
For the purpose of this problem, we will return 0 when needle
is an empty string. This is consistent to C's strstr() and Java's indexOf().
My soultion:
class Solution:
def strStr(self, haystack, needle):
"""
:type haystack: str
:type needle: str
:rtype: int
"""
if len(needle) == 0:
return 0
if needle in haystack:
return haystack.index(needle)
return -1
'DataStructure > Strings' 카테고리의 다른 글
Longest Common Prefix (0) | 2018.10.25 |
---|---|
Count and Say (0) | 2018.10.25 |
String to Integer (atoi) (0) | 2018.10.23 |
Valid Palindrome (0) | 2018.10.23 |
Valid Anagram (0) | 2018.10.23 |