Day 16: Exceptions - String to Integer

Task 
Read a string, , and print its integer value; if  cannot be converted to an integer, print Bad String.

Note: You must use the String-to-Integer and exception handling constructs built into your submission language. If you attempt to use loops/conditional statements, you will get a  score.

Input Format

A single string, .

Constraints

• , where  is the length of string .
•  is composed of either lowercase letters () or decimal digits ().

Output Format

Print the parsed integer value of , or Bad String if  cannot be converted to an integer.

Sample Input 0

3

Sample Output 0

3

Sample Input 1

za

Sample Output 1

Bad String

Explanation

Sample Case  contains an integer, so it should not raise an exception when we attempt to convert it to an integer. Thus, we print the . 
Sample Case  does not contain any integers, so an attempt to convert it to an integer will raise an exception. Thus, our exception handler prints Bad String.

풀이

package Day16;

import java.util.Scanner;

public class Solution {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        String S = in.next();
        try {
            System.out.println(Integer.parseInt(S));
        } catch (NumberFormatException e){
            System.out.println("Bad String");
        }
    }
}