DataStructure/Array
Two Sum
ND Paul Kim
2018. 10. 29. 18:30
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9, Because nums[0] + nums[1] = 2 + 7 = 9, return [0, 1].
My solution:
class Solution:
def twoSum(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: List[int]
"""
for i in range(len(nums)):
if target - nums[i] in nums:
if i != nums.index(target - nums[i]):
return [i, nums.index(target - nums[i])]
return None
Good solution:
class Solution:
def twoSum(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: List[int]
"""
dist = {}
for i in range(len(nums)):
if target - nums[i] in dist:
return [dist[target - nums[i]], i]
dist[nums[i]] = i
return None
Instead of using dict(), use {}.
It's good for runtime.